Problem:
Given an integer n, you may perform only the following operations:
- If n is divisible by 2, you may perform:
n = n / 2 - You may increment n by 1:
n = n + 1
Your goal is to compute the smallest number of operations required to reduce n to 1.
Example:
n = 1
→ output = 0
This is a classic greedy + bit-manipulation problem.
Two operations are allowed:
- If
nis even, dividing by 2 is always optimal. - If
nis odd, we must choose between:n + 1- (implicitly)
n - 1through repeated divides
The key insight comes from binary representation:
- For odd numbers, using
+1is only better when it leads to more trailing zeroes in binary (meaning more subsequent/2operations). - Special case:
n = 3→ always choosen - 1path (i.e., go to 2).
This produces an O(log n) time greedy solution.
This problem tests whether the candidate knows:
- How to analyze binary patterns
- Greedy correctness reasoning
- Minimizing operations on integer reduction
It’s similar to problems seen in FAANG interviews (e.g., LeetCode 397).
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