Given a log file, find the top N most talkative users
10:00 <john> hi!
10:01 <maria> hello!
10:07 <john> can you link the design?
// Returns e.g.
// [
// {username: "john", wordCount: 1},
// {username: "maria", wordCount: 1},
// {username: "john", wordCount: 5}
// ]
public List<UserWordCount> parseLog(String filepath) {// Implemented for you}Parse each line, extract username and message, count words, aggregate per user in a map, sort by total word count (desc), return top N.
Given a chat log, count how many words each user has spoken and return the top N most talkative users.
Key steps:
- Parse each log line to extract the username.
- Split the message to count the number of words.
- Accumulate counts in a HashMap.
- Sort users by total word count (descending) and return the top N.
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